-3p(-2-3)+p-2^2=-(2p+4)

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Solution for -3p(-2-3)+p-2^2=-(2p+4) equation: 



-3p(-2-3)+p-2^2=-(2p+4)

We move all terms to the left:

-3p(-2-3)+p-2^2-(-(2p+4))=0

We add all the numbers together, and all the variables

-3p(-5)+p-(-(2p+4))-2^2=0

We add all the numbers together, and all the variables

p-3p(-5)-(-(2p+4))-4=0

We multiply parentheses

p+15p-(-(2p+4))-4=0



We calculate terms in parentheses: -(-(2p+4)), so:

-(2p+4)

We get rid of parentheses

-2p-4

Back to the equation:

-(-2p-4)



We add all the numbers together, and all the variables

16p-(-2p-4)-4=0

We get rid of parentheses

16p+2p+4-4=0

We add all the numbers together, and all the variables

18p=0

p=0/18

p=0

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